(x^2+4)^2+32=12x^2+48

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Solution for (x^2+4)^2+32=12x^2+48 equation: 



(x^2+4)^2+32=12x^2+48

We move all terms to the left:

(x^2+4)^2+32-(12x^2+48)=0

We get rid of parentheses

-12x^2+(x^2+4)^2-48+32=0

We add all the numbers together, and all the variables

-12x^2+(x^2+4)^2-16=0

We move all terms containing x to the left, all other terms to the right

-12x^2+(x^2+4)^2=16

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